Raising the Window Washer: A Trickier Problem Than It Looks

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The discussion revolves around the challenge of calculating the force a window washer must exert to raise herself at a constant speed using a bucket-pulley system. The initial advice suggests that since the acceleration is zero, she only needs to pull her weight, calculated at 604.7 N. However, the problem hints that there are two upward forces acting on her: one from the rope on the basket and another from the rope on her hands. Participants express confusion over the calculations and suggest various adjustments, but none seem to resolve the issue. The complexity of the problem indicates that a deeper understanding of the forces at play is necessary.
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Ok, I tried this and even found on this forum that someone asked the same question before, but I tried their advice and the answer was still wrong. The problem is that :
---- A window washer pulls herself upward using the bucket-pulley apparatus ...How hard must she pull downward to raise herself slowly at constant speed? The mass of the person plus the bucket is 61.7kg.----

The advice given on this forum was that since she is moving at a constant speed, the acceleration is zero...so she just needs to pull her (plus the bucket's) weight. I calculated this (W=mg) and got 604.7 N, but the program says I'm wrong. And then it gave a hint : This problem is trickier than it looks. There are two upward forces acting on the girl. One is exerted by the rope on the top of the basket. The other is exerted by the rope on her hands.

So does anyone have any advice on what to do? Much thanks :o)
 
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maybe make it 2N? multiply n times 2... if the rope goes half way around the pulley, its 2N, at least that's what my program says... try that?
 
o like 604.7 times 2? I just tried that and it says it's wrong
 
hrm, maybe I am doing the wrong one then, sheesh, I am gettin so confused lately... sorry i couldn't be of more help
 
lol np, thanks for trying tho! :)
 
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