Quantinzation of Energy & Planck help

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To calculate the frequency of a photon emitted when an electron transitions between two energy levels, the difference in energy levels must be determined using E=hf, where h is Planck's constant. The photon frequency is equal to the energy difference divided by Planck's constant. For FM radio signals, the wavelength can be calculated using the formula c=fλ, where c is the speed of light and f is the frequency in hertz. A conversion from MHz to hertz is necessary for accurate calculations. The discussions clarify the correct application of these formulas to find both frequency and wavelength.
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Can anyone help me with this question? Thanx



Calculate the frequency of the photon emitted when an electron in an atom changes from (-2.42e-19 joules) to (-21.76e-19 joules).

I know that I'm going to use E=hf and h=6.63e-34. I'm not sure what I do with the 2 energy levels, do i subtract them?
 
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A photon is emitted when an electron falls into a lower energy level. The photon must equal the difference in energy due to conservation of energy. E will equal the difference in energy levels. You can then use algebra to determine f, the frequency.
 
Electromagnectic Wave Help

Can anyone help me with this problem?

What is the wavelength for an FM radio signal if the number on the dial reads 98.5 MHz? C=3e8

I know that c=f wavelength, and MHz is a million hertz I thought I could do 1E6 x 98.5=9.85e7 and then I could just solve for the wavelength with 3e8=9.85e7wavelength but I keep getting the wrong answer. Am i missing something??
 
What answer are you getting?
 
My mistake I got that one it is 3.05. But another where there frequency is 25 GHz. To find the wavelength on this one i would 3e8/25e9=0.012, and that is wrong. Thanx
 
If its 25 ghz... then 0.012m is correct...
 
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