Quantum Mechanics: Finding Wavefunction

CuriosLearner
Messages
5
Reaction score
0

Homework Statement


The wave function Ψ of a quantum mechanical system described by a Hamiltonian H ̂ can be written as a linear combination of linear combination of Φ1 and Φ2 which are eigenfunctions of H ̂ with eigenvalues E1 and E2 respectively. At t=0, the system is prepared in the state Ψ0=4/5 Φ1+3/5 Φ2 and then allowed to evolve with time. The wave function at time T=1/2 {h/(E1-E2)} will be (accurate within a phase)
a) 4/5 Φ1 + 3/5 Φ2
b) Φ1
c) 4/5 Φ1 - 3/5 Φ2
d) Φ2
e) 3/5 Φ1 + 4/5 Φ2
f) 3/5 Φ1 - 4/5 Φ2

Homework Equations


Ψ(x,t) = \sumCn Φn(x) exp(-i En 2π t/h)

The Attempt at a Solution


I tried evaluate the Ψ for given value of time but couldn't get any relationship between E1 and E2 to simplify it further. I don't know if this approach is right.
 
Physics news on Phys.org
Show your work.
 
Ψ(x,T) = 4/5 Φ1 exp{-i π E1/(E1-E2)} + 3/5 Φ2 exp{-i π E2/(E1-E2)}
= 4/5 Φ1 exp{-i π (1+ E2/(E1-E2))} + 3/5 Φ2 exp{-i π E2/(E1-E2)}
= exp{-i π E2/(E1-E2)}[4/5 Φ1 exp{-i π} + 3/5 Φ2]
= exp{-i π E2/(E1-E2)}[-4/5 Φ1 + 3/5 Φ2]
I am stuck here.
 
CuriosLearner said:
Ψ(x,T) = 4/5 Φ1 exp{-i π E1/(E1-E2)} + 3/5 Φ2 exp{-i π E2/(E1-E2)}
= 4/5 Φ1 exp{-i π (1+ E2/(E1-E2))} + 3/5 Φ2 exp{-i π E2/(E1-E2)}
= exp{-i π E2/(E1-E2)}[4/5 Φ1 exp{-i π} + 3/5 Φ2]
= exp{-i π E2/(E1-E2)}[-4/5 Φ1 + 3/5 Φ2]
I am stuck here.

exp{-i π E2/(E1-E2)} is a constant phase factor, so "accurate within a phase" your wavefunction is just the stuff in square brackets.
 
gabbagabbahey said:
exp{-i π E2/(E1-E2)} is a constant phase factor, so "accurate within a phase" your wavefunction is just the stuff in square brackets.

Does this really solve the problem? I mean we can add a π further to the overall phase (can we?) and it will be the option C that is listed there. Is this correct?
Also I was wondering if E1<E2 always. Because in that case the time T mentioned would be negative. What would it imply?
 
CuriosLearner said:
Does this really solve the problem? I mean we can add a π further to the overall phase (can we?) and it will be the option C that is listed there. Is this correct?

I'm not sure what you mean here by "add a π further to the overall phase". Do you understand what a phase factor is in this context? Do you understand why we can safely ignore a constant phase factor?

Also I was wondering if E1<E2 always. Because in that case the time T mentioned would be negative. What would it imply?

Negative time is nothing special, you only measure differences in time. That said, it is probably safe to assume that E1<E2 for this problem. You should also realize that both E1 &E2 are real-valued constants (why?) and thus exp{-i π E2/(E1-E2)} is just some complex-valued constant.
 
gabbagabbahey said:
I'm not sure what you mean here by "add a π further to the overall phase". Do you understand what a phase factor is in this context? Do you understand why we can safely ignore a constant phase factor?
I think that is because any constant phase factor gets canceled out when you write the Schrodinger's equation. So ψ is only accurate within a constant complex phase. I actually meant 'iπ' to be added to that constant phase so as to make it equal to option C there. Also physical significance of the phase should be same as that of phase in any wave equation.

gabbagabbahey said:
Negative time is nothing special, you only measure differences in time. That said, it is probably safe to assume that E1<E2 for this problem. You should also realize that both E1 &E2 are real-valued constants (why?) and thus exp{-i π E2/(E1-E2)} is just some complex-valued constant.
Yes E1 and E2 are real because they are eigenvalues Hamiltonian which is Hermitian. But I would like to know when E1>E2 particularly. Also regarding negative time, doesn't it mean that we are finding the wavefunction before t=0? i.e. before the system was prepared in such state?
Kindly excuse my lack of knowledge and understanding. I am only a beginner in quantum mechanics. Thanks a lot for your help.
 
Back
Top