Quantum mechanics , total orbital angular momentum?

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SUMMARY

The discussion centers on calculating the total orbital angular momentum of a hydrogen atom in a state with principal quantum number n=4. The largest permitted value of the azimuthal quantum number l is 3, leading to the allowed magnetic quantum numbers m ranging from -3 to 3. The total orbital angular momentum is represented by L², calculated as l(l+1)ħ², yielding a value of 12ħ² for l=3. The relationship between l, m, and their respective angular momentum components is clarified, emphasizing that total orbital angular momentum encompasses more than just the z-component.

PREREQUISITES
  • Understanding of quantum numbers (n, l, m)
  • Familiarity with angular momentum in quantum mechanics
  • Knowledge of the hydrogen atom's quantum states
  • Concept of operators in quantum mechanics, specifically L² and Lz
NEXT STEPS
  • Study the derivation of L² = l(l+1)ħ² in quantum mechanics
  • Explore the implications of quantum numbers on atomic structure
  • Learn about the significance of total angular momentum in quantum systems
  • Investigate the relationship between orbital and spin angular momentum
USEFUL FOR

Students of quantum mechanics, physicists focusing on atomic structure, and educators teaching advanced quantum theory concepts.

Outrageous
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Homework Statement



A hydrogen atom is identified as being in a state with n=4. What is the magnitude of the total orbital angular momentum for the largest permitted value of l?

Homework Equations


n>l, l is bigger or equal to m

The Attempt at a Solution


The allowed l= 3,2,1
The allowed m for largest l= 3,2,1,0,-1,-2,-3
Total orbital angular momentum is the sum of all Lz or L^2?
Ans, total= 3+2+1+0 +(-1)+(-2)+(-3)=0?
L^2= 3(3+1)hbar
What is the total orbital angular momentum?
Please guide ,thanks
 
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Outrageous said:

Homework Statement



A hydrogen atom is identified as being in a state with n=4. What is the magnitude of the total orbital angular momentum for the largest permitted value of l?

Homework Equations


n>l, l is bigger or equal to m

The Attempt at a Solution


The allowed l= 3,2,1
The allowed m for largest l= 3,2,1,0,-1,-2,-3
Total orbital angular momentum is the sum of all Lz or L^2?
Ans, total= 3+2+1+0 +(-1)+(-2)+(-3)=0?
L^2= 3(3+1)hbar
What is the total orbital angular momentum?
Please guide ,thanks
Read your textbook and notes and answer the following questions:
  1. What does ##\vec{L}^2## physically represent?
  2. What about ##L_z##?
  3. How are ##l## and ##m## related to ##\vec{L}^2## and ##L_z##?
 
vela said:
Read your textbook and notes and answer the following questions:
  1. What does ##\vec{L}^2## physically represent?
  2. What about ##L_z##?
  3. How are ##l## and ##m## related to ##\vec{L}^2## and ##L_z##?

##\vec{L}^2## mean the angular momentum square
##L_z## angular momentum in z direction
##\vec{L}^2##=l(l+1)\hbar and ##L_z##=m\hbar.
Total orbit angular momentum is j?
J=l-(1/2) or l+(1/2)
 
Outrageous said:
##\vec{L}^2## mean the angular momentum square
##L_z## angular momentum in z direction
##\vec{L}^2=l(l+1)\hbar## and ##L_z=m\hbar##.
That should be ##\vec{L}^2=l(l+1)\hbar^2##. Total orbital angular momentum means not just the z-component. ##m## and ##l## are quantum numbers, not angular momenta.

Total orbit angular momentum is j?
J=l-(1/2) or l+(1/2)
The key word here is orbital. Which observable corresponds to orbital angular momentum?
 

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