Quantum Numbers for a couple of electrons Help needed

AI Thread Summary
The discussion focuses on determining the quantum numbers (QNs) for electrons in the configurations 4p^2 and 6s^2. For 4p^2, the correct quantum numbers are n=4, l=1, m=-1 and 0, with spins of +1/2 for both electrons. For 6s^2, the quantum numbers are n=6, l=0, m=0, and spins of +1/2. There was some confusion regarding the filling of orbitals in the p subshell, but it was clarified that both electrons in 4p^2 can have positive spins. The conversation emphasizes the proper assignment of quantum numbers based on electron configurations.
mathzeroh
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Good evening scholars! i just had a couple of questions about QNs.

ok so the problem says:

Give the sets of {n, l, m, s} for the electrons in:
a) 4p^2
b) 6s^2

i just want to see if I'm on the right track. here's what i put for the first one (a):

n= 4
l= 1
m= -1, 0
s= +/- 1/2

thanks!
 
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Keep in mind that m is from -L TO +L
m would be -1, 0 , and +1
your spin is fine

what about the 6s^2
so obvious n =6,
p = ?? for the s shell waht is the P value?
and thus what is the m value and s values correspondingly?
 
true, but i thought since it said that only the first two orbitals of the "p" subshell contain electrons, i thought that since the lowest level energy shells get filled up first, only the -1, and 0 would be the only possible orbitals where electrons are located. is that wrong of me? :frown:

as for the 6^2, ok let's see:
n=6 like you said, l=0 and m=0 (because there's only one orbital in the "s" subshell so that means that it is in the 0 orbital - or middle i suppose?). s= plus or minus 1/2 and l-
 
mathzeroh said:
true, but i thought since it said that only the first two orbitals of the "p" subshell contain electrons, i thought that since the lowest level energy shells get filled up first, only the -1, and 0 would be the only possible orbitals where electrons are located. is that wrong of me? :frown:

as for the 6^2, ok let's see:
n=6 like you said, l=0 and m=0 (because there's only one orbital in the "s" subshell so that means that it is in the 0 orbital - or middle i suppose?). s= plus or minus 1/2 and l-

WHOOPS SORRY

my mistake, for the 4p2 you are correct the p orbital would be filled up for the -1 and 0 part
however, since you fill in teh positive spins in first both the electrons have positive spin
 
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