Quantum Numbers for a couple of electrons Help needed

Click For Summary
SUMMARY

The discussion focuses on determining the quantum numbers (QNs) for the electron configurations 4p2 and 6s2. For 4p2, the quantum numbers are n=4, l=1, m=-1, 0, and s=±1/2. For 6s2, the quantum numbers are n=6, l=0, m=0, and s=±1/2. The participants clarify that the m values for the p subshell range from -1 to +1, and emphasize that the s subshell has only one orbital, thus m=0.

PREREQUISITES
  • Understanding of quantum numbers: principal (n), azimuthal (l), magnetic (m), and spin (s).
  • Familiarity with electron configurations and subshells in atomic structure.
  • Knowledge of the Aufbau principle for filling electron orbitals.
  • Basic grasp of the periodic table and the arrangement of elements.
NEXT STEPS
  • Study the Aufbau principle in detail to understand electron filling order.
  • Learn about Hund's rule and its implications for electron configurations.
  • Explore the significance of quantum numbers in determining electron behavior.
  • Research the differences between s, p, d, and f subshells and their respective quantum numbers.
USEFUL FOR

Students of chemistry, educators teaching atomic structure, and anyone interested in mastering quantum mechanics and electron configurations.

mathzeroh
Messages
98
Reaction score
0
Good evening scholars! i just had a couple of questions about QNs.

ok so the problem says:

Give the sets of {n, l, m, s} for the electrons in:
a) 4p^2
b) 6s^2

i just want to see if I'm on the right track. here's what i put for the first one (a):

n= 4
l= 1
m= -1, 0
s= +/- 1/2

thanks!
 
Physics news on Phys.org
Keep in mind that m is from -L TO +L
m would be -1, 0 , and +1
your spin is fine

what about the 6s^2
so obvious n =6,
p = ?? for the s shell what is the P value?
and thus what is the m value and s values correspondingly?
 
true, but i thought since it said that only the first two orbitals of the "p" subshell contain electrons, i thought that since the lowest level energy shells get filled up first, only the -1, and 0 would be the only possible orbitals where electrons are located. is that wrong of me? :frown:

as for the 6^2, ok let's see:
n=6 like you said, l=0 and m=0 (because there's only one orbital in the "s" subshell so that means that it is in the 0 orbital - or middle i suppose?). s= plus or minus 1/2 and l-
 
mathzeroh said:
true, but i thought since it said that only the first two orbitals of the "p" subshell contain electrons, i thought that since the lowest level energy shells get filled up first, only the -1, and 0 would be the only possible orbitals where electrons are located. is that wrong of me? :frown:

as for the 6^2, ok let's see:
n=6 like you said, l=0 and m=0 (because there's only one orbital in the "s" subshell so that means that it is in the 0 orbital - or middle i suppose?). s= plus or minus 1/2 and l-

WHOOPS SORRY

my mistake, for the 4p2 you are correct the p orbital would be filled up for the -1 and 0 part
however, since you fill in the positive spins in first both the electrons have positive spin
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 1 ·
Replies
1
Views
629
Replies
17
Views
3K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 30 ·
2
Replies
30
Views
8K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
28
Views
2K