If I were to drive south at 20.0 m/s for 3 min, then turn west and travel at 25 m/s for 2 min, and finally travel northwest at 30.0 m/s for 1.00 min. what would my total vector displacement be? I start out by converting minutes to seconds, so I have position vectors; 1800m to south, 3600m west, and 1800m NorthWest. Then using the respective vector units, I add them up, and square each component, and take the square root. I keep getting a different answer, please help. Displacement Vector = Sqrt ( (3600 +1800cos45 + 0)i ^2 + ((1800sin45 +3000)^2 j)) Am i on the wrong track here, this is REALLY bugging me out!!!