Find the Coordinates of Point B using Cross Product

AI Thread Summary
To find the coordinates of point B, the cross product of vectors AC and AD is essential, as it yields a vector perpendicular to both. The order of the vectors in the cross product affects the direction of the resulting vector, but not the ability to find point B. The cross product itself does not directly provide the coordinates of B; instead, it gives a direction that can be scaled to the length of 7.09 meters. By normalizing the cross product and multiplying by 7.09, two possible coordinates for B can be determined, one being the negative of the other. This approach effectively resolves the problem of finding point B's coordinates.
Melawrghk
Messages
140
Reaction score
0

Homework Statement


Point A is at (0,3,0), D(0, 0, 3), C(4, 0, 0) and B(x,y,z). The bar AB is 7.09 m long and is perpendicular to the bars AC and AD. Use the cross product to determine the coordinates of x, y, and z.

Homework Equations


The cross product matrix thing...


The Attempt at a Solution


I found the eqations for AC and AD. I know that if I find their cross product, I will get AB, which is essentially what I'm looking for.
AC = 4i-3j+0k
AD = 0j-3j+3k

When I found the cross product of them in this form, I got it wrong. Also, I'm not sure which order to put them in, which one goes first, AC or AD? I now am attempting to convert them to unit vectors and do the cross product with those, but again, I'm not sure about the order. Help?

Thanks
 
Physics news on Phys.org
Melawrghk said:

Homework Statement


Point A is at (0,3,0), D(0, 0, 3), C(4, 0, 0) and B(x,y,z). The bar AB is 7.09 m long and is perpendicular to the bars AC and AD. Use the cross product to determine the coordinates of x, y, and z.

Homework Equations


The cross product matrix thing...

The Attempt at a Solution


I found the eqations for AC and AD. I know that if I find their cross product, I will get AB, which is essentially what I'm looking for.
AC = 4i-3j+0k
AD = 0j-3j+3k

When I found the cross product of them in this form, I got it wrong. Also, I'm not sure which order to put them in, which one goes first, AC or AD? I now am attempting to convert them to unit vectors and do the cross product with those, but again, I'm not sure about the order. Help?

Thanks

I don't think it's going to make a difference as to whether you do AC X AD or AD X AC. Won't the sign of the Resulting vector still be along the direction of AB but the sign of the coefficients of the components i,j,k will be reversed?

When I did the X-product of AD X AC I got in i,j,k an AB direction Resultant of (9,12,12), and for the AC X AD product got (-9,-12,-12), but it nominally points in the opposite direction. Knowing the direction of the resultant you should be able to solve for the intersection of B(x,y,z) no?
 
Last edited:
You are not asked for the cross product itself. The cross product will give you a vector perpendicular to both AC and AD but NOT the point (x,y,z) you want. To find a vector perpendicular to both AC and AD AND with length 7.09, divide the cross product by its length (to get a vector with length 1) and then multiply that unit vector by 7.09. There are actually two possible answers, one with coordinates the negative of the other.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top