Solving a Quick Math Homework: Finding sin(x/2) from sin(x) = 8/17

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To find sin(x/2) from sin(x) = 8/17, use the identity sin²(x/2) = (1 - cos(x))/2. First, calculate cos(x) using cos²(x) = 1 - sin²(x), which leads to cos(x) = ±15/17. This results in sin(x/2) = √((17 ± 15)/34). The final possible values for sin(x/2) are √(16/17) or √(1/17). Understanding that sin(2x) does not equal 2sin(x) is crucial, as it reflects the non-linear nature of the sine function.
Elijah the Wood
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If sin(x) = 8/17, what would sin(x/2) = ?

I knew how to get 8/17, but i have no idea where to go from here
Would you just times the denominator by 2?
 
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Remember that:
\sin^{2}\frac{x}{2}=\frac{1-\cos(x)}{2}
Since:
\sin^{2}x+\cos^{2}x=1
we have, in this particular case:
\cos^{2}x=1-(\frac{8}{17})^{2}=(\frac{15}{17})^{2}
Or:
\cos(x)=\pm\frac{15}{17}
Hence,
\sin(\frac{x}{2})=\sqrt{\frac{17\pm15}{34}}

You need therefore the SIGN of cosine to determine your value completely.
 
Solve sin(x) = 8/17 for x
Halve x, then put it back into sin.
 
since sin(x/2)=root17+-15/34 would the final answer be sin (x/2)=root+-16/17?

side note: why is sin2x not equal to 2sinx? Is it because in sin2x you are doubling the angle and in 2sinx you're doubling the whole answer?
 
side note: why is sin2x not equal to 2sinx? Is it because in sin2x you are doubling the angle and in 2sinx you're doubling the whole answer?

Doubling the angle does not, in general double the value of the sin.
This is because sin(x) is a NON-linear function of the argument.

And no, your answers are EITHER:
\sin(\frac{x}{2})=\sqrt{\frac{16}{17}}
OR:
\sin(\frac{x}{2})=\sqrt{\frac{1}{17}}
 
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