I Quiz question: Who Dies If 'E' Pushes The Stone?

[swampwiz]

https://scontent-arn2-1.xx.fbcdn.net/v/t1.0-9/31131486_10155149285526260_4418766605865975808_n.jpg?_nc_cat=0&oh=53840620f886c5dab249cc2a8ff1010b&oe=5B4E8CA6

 

[russ_watters]

https://scontent-arn2-1.xx.fbcdn.net/v/t1.0-9/31131486_10155149285526260_4418766605865975808_n.jpg?_nc_cat=0&oh=53840620f886c5dab249cc2a8ff1010b&oe=5B4E8CA6

What is your answer and why?

 

[swampwiz]

What is your answer and why?

I think that if anything, A gets hit, but the stone could roll all the way through (besides, A could duck). I'm presuming that the notch fits perfectly over D, and there would be only horizontal momentum going to the seesaw, and with the other stone being heavier (i.e., no notch), it would not crush C, and would vault over the other stone (because of the kinetic energy), clearing B as well.

 

[Some new guy]

I think that if anything, A gets hit, but the stone could roll all the way through (besides, A could duck). I'm presuming that the notch fits perfectly over D, and there would be only horizontal momentum going to the seesaw, and with the other stone being heavier (i.e., no notch), it would not crush C, and would vault over the other stone (because of the kinetic energy), clearing B as well.

To start it off, there is probably a way to calculate the circumference of that notched stone. Then calculate the distance of that hypotenuse.