Radius of core, using densities

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Homework Help Overview

The problem involves calculating the radius of a planet's core, given its average density and the densities of its materials, specifically quartz and iron. The planet has a defined radius and is composed of quartz up to the core, which is made of iron.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the planet's total volume and the volumes of its core and mantle. There are attempts to derive equations relating mass and volume based on density. Some participants express confusion about the algebraic manipulations needed to isolate the core's radius.

Discussion Status

There are multiple approaches being explored, with some participants providing equations and substitutions to relate the core's volume to the overall mass and density of the planet. Guidance has been offered, but there is no explicit consensus on the correctness of the derived values or methods.

Contextual Notes

Participants are working under the constraints of the problem's parameters, including specific densities and the total radius of the planet. There is an acknowledgment of the complexity introduced by the cubic relationship in the volume formula.

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Homework Statement


A planet with R=4000km and [tex]\rho[/tex]avg=5g/cm3. The planet is made of quartz all the way to the core, which is made of iron. The densities of quart and iron are [tex]\rho[/tex]quartz=2.65g/cm3 and [tex]\rho[/tex]iron=7.874g/cm3. Calculate the radius of the core.


Homework Equations


[tex]\rho[/tex]=M/V
Vsphere=4/3[tex]\pi[/tex]r3


The Attempt at a Solution


I solved for Mplanet=[tex]\rho[/tex]avg=5g/cm3*4/3[tex]\pi[/tex]4000km and got 1.34*1027g. Then with assuming the Mplanet=MTot. Qrtz+MTot. Iron, I tried using various substitutions of my unknowns and I can't get anywhere close to being able to solve for any of them. I know it's some simple calculus, but I am lost and don't remember how to do this. The biggest problem for me is that the radius is cubed and I forgot what to do to solve for that.
Any fresh ideas would help a lot.
Thanks
 
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The volume of the planet is equal to the volume of the core plus the volume of the mantle.
That's one equation. Then you have your mass equation.
From these two you can substitute for the volume of the mantle to find the volume of the core and thus arrive at core radius.
 
So after a bunch of substitutions and algebra solving for Vcore, I got
Vcore=([tex]\rho[/tex]avg*V[tex]\rho[/tex]planet - [tex]\rho[/tex]mantle*Vplanet) / ([tex]\rho[/tex]core - [tex]\rho[/tex]mantle) and got 1.206*1026g/cm3.
Solving for the radius I got
r=[tex]\sqrt[3]{V<sub>core</sub>/(4pi/3)}[/tex] and got 3.0665*108cm which is 3065km, roughly 75% of the planet's r. Sound right?
 
No I don't think so...

VolumePlanet = VolumeMantle + VolumeCore

now

VolumeMantle = VolumePlanet - VolumeCore

so substituing

VolumePlanet = (VolumePlanet - VolumeCore) + VolumeCore

Now why did we do that? Because if we now multiply the volumes by the densities to get the masses, things are much more interesting...

VolumePlanet * DensityAverage= ((VolumePlanet - VolumeCore) * DensityMantle) + (VolumeCore * DensityCore)

Now we know all those numbers except VolumeCore. We are on our way...

I've probably given you too much help but I couldn't see any other way.
 

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