Rearranging Exponential Curve Equation

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AI Thread Summary
The discussion centers on rearranging the exponential curve equation V = Vo e^(-t/RC) to find the time it takes for a capacitor to discharge from 120 V to 15 V. The user correctly identifies the need to use the natural logarithm (ln) to isolate the variable t. However, they struggle with applying the logarithm correctly, leading to incorrect calculations. Other participants suggest the proper method of taking the natural logarithm of both sides of the equation to solve for t. Ultimately, the goal is to demonstrate that the discharge time is approximately 3 seconds.
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Homework Statement



Hello. I'm afraid it's quite a simple and unexciting problem I have. Basically, I can't remember how to rearrange the equation for an exponential curve:

The capacitor has a capacitance of 0.63 mF and the resistance in the discharge circuit is
2.4 kΩ.

(i) Calculate the time constant of the discharge circuit. This I can do: -t = RC.
(ii) Show that it takes about 3 s to discharge the capacitor from 120 V to 15 V.


Homework Equations



V = Vo e^-t/RC

The Attempt at a Solution



I remember it's the above equation I need to use. And I remember it's to do with the "ln" button on my calculator. But I can't remember how, when or where I use it. I know it's meant to "get rid of" the e and make my -t/RC "un-square" themselves so I can rearrange the equation. Apologies for my terrible lack of physics vocabulary :P.

I've tried a combination of things, enclosing the whole equation in ln( ) but I can't get the right answer (which is 3.14 seconds) as I am not rearranging it properly.

I would appreciate any help anyone has.
 
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mandos said:
… Show that it takes about 3 s to discharge the capacitor from 120 V to 15 V.

V = Vo e^-t/RC

Hi mandos! :smile:

You're given V and V0, and you want to calculate t.

So just "logify" the whole equation :biggrin:

-t/RC = … ? :wink:
 
Hi, am sorry to be a pain but that makes no sense to me.

In my calculator, I try ln ((V*R*C)/(Vo)) and it gives me -1.66s.
 
mandos said:
Hi, am sorry to be a pain but that makes no sense to me.

In my calculator, I try ln ((V*R*C)/(Vo)) and it gives me -1.66s.

But you didn't "logify" …

ln(V) = ln(Vo e-t/RC) :wink:
 
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