Rectangle tipping point on ramp

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Homework Help Overview

The problem involves determining the maximum angle theta at which a uniform rectangular box can be placed on a ramp without tipping over. The context centers around concepts of torque and equilibrium in a physics setting.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the role of torque and the importance of identifying the pivot point when the box begins to tip. Questions arise about the location of forces and how to relate angles to the tipping point.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to analyze the problem, including the use of torque equations and geometric reasoning. There is a focus on visualizing the forces and their relationship to the pivot point.

Contextual Notes

Participants are considering the implications of friction and the geometry of the setup, as well as the need to relate angles in the torque calculations. There is an emphasis on understanding the balance of forces just before tipping occurs.

xkirkx
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A uniform 10 cm x 20 cm box is placed on a ramp that rises at angle theta above the horizontal. Assuming that there is enough friction to prevent this box from sliding, what is the largest that theta can be without tipping it over?

do i use torque = r*F*sin*(theta), if so how do i use it?
 
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Torques involve a force about some rotation axis, or pivot point. Start by asking yourself, what is the important pivot point in this problem. When the box starts to tip, where does it rotate about? What is the force that makes this torque and where would it be located?
 
the force is located on the center of mass of the rectangle, the pivot point is the bottom corner that is lowest on the ramp. i just don't know how to put it all together.
 
xkirkx said:
the force is located on the center of mass of the rectangle, the pivot point is the bottom corner that is lowest on the ramp. i just don't know how to put it all together.

Ask yourself what angle the Center of Mass makes with the bottom corner when it is flat. How much does it need to be tipped then to get it to fall over?
 
You can either use the torque forumula, or draw a picture and use geometry to find the angle. Imagine that the ramp is not there and that something is holding the bottom corner in place. At certain angles the gravity force vector will be the the left of the pivot point and the box will rotate one way. At other angles, the gravity force vector will on the right side of the pivot point and the box will rotate the other way. Where would the gravity force vector be pointing relative to the pivot point to just balance the box, just before it tips one way or the other? If you can picture that, then geometry will give you the answer.

If you need to use vectors and torque equations, then what is the torque at the balance point just before the box tips? That gives you one side of the equation (the torque). What goes into the sin() is not just the ramp angle theta. It is the angle between the gravity vector and the radial vector from the center of gravity to the pivot point that goes into sin(). You need to relate that angle to theta. So some function of theta will be inside the sin().
 

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