Is My Redrawn Resistor Circuit Correct?

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A new member seeks confirmation on the accuracy of their redrawn resistor circuit, specifically focusing on the consolidation of resistors in area ABC. Initial feedback indicates that while the second and third circuits are equivalent to the first, there are errors in the arrangement, particularly regarding the 4 Ω and 6 Ω resistors, which cannot be combined as initially drawn. The correct approach involves extending the 10 Ω and 6 Ω resistors to a horizontal line, allowing for proper consolidation of the 6 Ω, 5 Ω, and 19 Ω resistors in parallel. The final calculation involves adding the resulting equivalent resistance in series with the 4 Ω resistor and then combining the last two resistors in parallel. The discussion concludes with the member confirming their understanding of the correct method.
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Hello, I am a new member, just signed up, I have browsed the forums for a bit and have always found some great info here...Today I have a question that I worked through, but really wanted a confirmation that I am on the correct path.
I attached a redrawing of a resistor circuit, if it is not correct any direction would be appreciated.

I am specifically looking at the area (ABC) in the drawing and wondering if I have consolidated the resistors correctly at that point.

Thank you

I hope the scan is legible enough.
 

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moto30 said:
Hello, I am a new member, just signed up, I have browsed the forums for a bit and have always found some great info here...Today I have a question that I worked through, but really wanted a confirmation that I am on the correct path.
I attached a redrawing of a resistor circuit, if it is not correct any direction would be appreciated.

I am specifically looking at the area (ABC) in the drawing and wondering if I have consolidated the resistors correctly at that point.

Thank you

I hope the scan is legible enough.
Hello moto30. Welcome to PF !

The second and third circuits are equivalent to the first.

After that there are errors.

The 4 Ω resistor is not in series with the 6 Ω resistor. You can't combine them like that.


In you first circuit, you have two points labeled c . You can split the left-hand one in two so that in the second and third circuits, the wires from the 10 Ω & 6 Ω resistors extend all the way down to the lower horizontal wire.
 
Thank You for the reply.

So once I extend the 10Ω and the 6Ω resistor to the horizontal line. would I just combine the 6Ω,5Ω, and 19Ω in parallel (which would be 2.38Ω); then add the 2.38Ω in series with the 4Ω and finally the last two in parallel?
 
moto30 said:
Thank You for the reply.

So once I extend the 10Ω and the 6Ω resistor to the horizontal line. would I just combine the 6Ω,5Ω, and 19Ω in parallel (which would be 2.38Ω); then add the 2.38Ω in series with the 4Ω and finally the last two in parallel?
Yes. That's right.
 
Great! Thank you again..
 

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