Regular Networks on Torus: Can't Have Pentagons as Faces?

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The discussion centers on the impossibility of creating a regular network on a torus with pentagonal faces, as dictated by the Euler characteristic formula V - E + F = 0. The user grapples with the concept that while pentagons can be drawn, they cannot tessellate to cover the torus completely. Each pentagon contributes edges and vertices, but the shared nature of these elements complicates the calculations. The confusion arises from the requirement for a regular network to have all shapes as pentagons, which is not feasible due to their inability to tessellate. Ultimately, the discussion highlights the mathematical constraints that prevent pentagons from forming a regular network on a torus.
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I'm asked to consider regular networks on a torus. I'm given that V - E + F = 0. I need to show it is impossible to have a regular network on a torus where the faces are pentagons; I don't understand that at all. Surely it is easy to have pentagons as faces… All you would need to is draw a pentagon on it, please tell me where I am not getting this.
 
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I suspect that what they mean is a network that completely covers the torus: every point on the torus in on or inside some pentagon.

Suppose your network consisted of n pentagons. Then there are n faces. How many edges are there? (Each pentagon has 5 edges, but each edge is shared by two pentagons.) How many vertices are there? (Each pentagon has 5 vertices but each vertex is shared by 3 pentagons.)

Now plug those numbers into the Euler equation.
 
Thanks :smile:
 
Erm writing this out, I'm confused again. How can all shapes be a pentagon in a regular network anyway? Pentagons don't tessellate.
 
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