Riding a Ferri wheel physic problem(help)

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The discussion revolves around a physics problem involving a student on a Ferris wheel, focusing on the normal force experienced at the highest and lowest points of the ride. The student weighs 656 N, and at the highest point, the normal force is 581 N. The main challenge is determining the normal force at the lowest point and how it changes if the wheel's speed is doubled. The student expresses confusion about the relationship between normal force and centripetal acceleration, questioning the validity of their equations. Ultimately, the problem is resolved, indicating that understanding the dynamics of forces on a Ferris wheel is crucial for solving such physics problems.
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Homework Statement



A student of weight 656 N rides a steadily rotating Ferris wheel (the student sits upright). At the highest point, the magnitude of the normal force N on the student from the seat is 581 N. (a) What is the magnitude of N at the lowest point? If the wheel's speed is doubled, what is the magnitude FN at the (b) highest and (c) lowest point?



Homework Equations



F=(mV^2)r a=v^2/r

The Attempt at a Solution


here are my "guesses", becuase i am so confused...
Fn is same as the centripetal acceleration, which is doward to the center of the wheel.
m=66.939 Fg = 656N
-581-656=66.939(-a) what I don't get is that if Fn= a, then this equation is not valid, i mean 581=a? I used this equation becuase it looks like the one in the textbook, but I didnt really get the equation.
 
Last edited:
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this problem is solved, so nvm
 
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