Rings and Fields - Write down the nine elements of F9

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SUMMARY

The discussion focuses on the mathematical structure of the field F9[i], where F9 is defined as Z/3Z. The field is constructed by introducing a new element 'i' such that i^2 = -1, allowing for the representation of complex numbers in this finite field. The nine elements of F9[i] are derived from combinations of elements a and b in F9, specifically {0, 1, 2} for both a and b. Additionally, it is established that every nonzero element in F9[i] possesses an inverse, confirming that F9[i] is indeed a field.

PREREQUISITES
  • Understanding of finite fields, specifically Z/3Z
  • Knowledge of complex numbers and their properties
  • Familiarity with polynomial arithmetic
  • Basic concepts of field theory and inverses
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Rings and Fields - Write down the nine elements of F9

Homework Statement



In F9 = Z/3Z, there is no solution of the equation x^2 = −1, just as in R. So “invent”
a solution, call it 'i'. Then 'i' is a new “number” which satisfies i^2 = −1. Consider
the set F9 consisting of all numbers a+bi, with a,b in F9. Add and multiply these
numbers as though they were polynomials in 'i', except whenever you get i^2 replace
it by −1.
(i) Write down the nine elements of F9 .
(ii) Show that every nonzero element of F9 has an inverse, so that F9 is a
field.


The Attempt at a Solution



I know I am supposed to show you that I've tried the question if i want an answer. Believe me, i have tried it. I am just really confused by the wording of the question and am not really sure what they are looking for in part a. Once i get part a, I am pretty sure id be able to get part b on my own.
 
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You are told that F9 = {a+bi | a,b in F9}. The first part is asking you to try out all the elements. So for example, 1+2i is an element.
The second part is asking you to show that for all a+bi in F9, there is some c+di such that (a+bi)(c+di) = 1. Try writing the inverse out using a and b in some way, then multiply it out to check if you are correct and get 1.
 

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