Archived Rolling Motion, Pebble stuck in a Tire by Static Friction

AI Thread Summary
A 1.2 g pebble is held in place by static friction of 3.6 N in a 0.76 m diameter tire as the car accelerates. The problem involves calculating the speed at which the pebble will fly out of the tire tread. Using the centripetal force equation, the maximum static friction is applied to find the velocity. The calculations yield a top wheel speed of approximately 33.76 m/s, which is halved to determine the car's speed at 16.88 m/s, aligning closely with the expected answer of 17 m/s. The approach used effectively demonstrates the relationship between static friction and the motion of the pebble.
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Homework Statement



A 1.2 g pebble is stuck in a tread of a 0.76 m diameter automobile tire, held in place by static friction that can be at most 3.6 N. The car starts from rest and gradually accelerates on a straight road. How fast is the car moving when the pebble flies out of the tire tread? I know the answer is 17 m/s however I don't know how to get it.

Homework Equations



v=(2*\pi*R)/T
v=ωR
\alpha=τ/I
I=1/2*M*R2
Fc=(m*v2)/2

The Attempt at a Solution



I tried using the centripetal force equation and rearranged for velocity, using the maximum static friction as my force. I then divided that number by 2 to get the speed in the centre of the wheel (since the speed at the top of the wheel is twice the speed of the vehicle).
 
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I believe the approach suggested by the OP gives the correct answer.

F=(mv^2)/r
Rearrange for v...
V=SQRT(Fr/m)
= SQRT(3.6*0.38/0.0012)
= 33.76m/S

This is the Velocity of the top of the wheel. The Velocity of the car is half that..

33.76/2=16.88m/S

Book answer 17m/S.
 
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