Rotation and curl? (Vector calc)

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Homework Statement


Give an example of a rigid body that has:
Rotation but not curl
Curl but not rotation
Rotation and curl
Neither rotation nor curl

The Attempt at a Solution


i don't even get what rotation is. Or curl, to be honest...*sigh* Maybe if you help me I can begin to understand. My book is making me want to bash myself over the head, it's so unhelpful x(
 
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Curl only applies to vector fields. The only vector field associated with a rigid body that you can take a curl of is the velocity field. Curl of a velocity field of a rigid body is simply proportional to the angular velocity of said body. So a rigid body is either rotating and has curl of velocity field, or it is not rotating and has zero curl of velocity field. With fluids you can get more creative, but with rigid bodies, these are your options. So I'm not sure the question makes sense. It's almost like answer to one of the questions, rotating rigid body, was accidentally put into the question, making the rest of it nonsensical.

Or I could be missing something. But it doesn't make any sense to me.
 
It says for a rigid body or fluid in motion...
I think she wants real world examples... I agree that it is confusing
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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