Rotation Velocity on a boomerang

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To calculate the rotation velocity of a boomerang with a period of 0.5 seconds, one must first determine the angular velocity, which can be derived from the period. The discussion clarifies that the term "rotation velocity" likely refers to tangential velocity, which is calculated by multiplying angular velocity (in rad/s) by the radius of rotation. Confusion arises from the distinction between linear and angular velocity, as well as the need to identify the stationary point around which the boomerang rotates. Ultimately, understanding these relationships is crucial for accurately calculating the boomerang's rotation dynamics.
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Homework Statement



How do I calculate the rotation velocity of a boomerang assuming that the period is like 0.5 seconds ? Considering a boomerang made of 3 rectangles, with an angle
of 120 degrees between two of those rectangles... According to internet..we must consider a velocity of throwing and a velocity of rotation and I don't know how to calculate this second one..

Homework Equations


3. The Attempt at a Solution

I was thinking of calculating angular velocity and then use V = w.R where R radius but I get values a little bit too high
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RicardoMarques said:
How do I calculate the rotation velocity of a boomerang assuming that the period is like 0.5 seconds ?
What do you mean by "rotation velocity"? If you already know that it rotates with a period of 0.5 seconds then calculation of its rotation rate would seem to be rather simple.

Are you, perhaps, asking to calculate the rotation rate based on the linear velocity of the boomerang and an assumption that the end of the blade that is held in the hand is stationary at launch?
 
jbriggs444 said:
What do you mean by "rotation velocity"? If you already know that it rotates with a period of 0.5 seconds then calculation of its rotation rate would seem to be rather simple.

Are you, perhaps, asking to calculate the rotation rate based on the linear velocity of the boomerang and an assumption that the end of the blade that is held in the hand is stationary at launch?

Is exactly that my question
 
RicardoMarques said:
Is exactly that my question
So we have the linear velocity of the boomerang as a given. Let's call that "v".

When we say that the boomerang is moving at v, it suggests that there is a point that is moving at v and that the boomerang is rotating around that moving point. That point has a name. Can you name it?
 
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I want to know this "a" assuming that the period is like 0.5... In the paper i read about it they call that velocity "a" rotation velocity... but is given i m/s and angular velocity is in rad/s, so I am kinda confused about this
 

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RicardoMarques said:
I want to know this "a" assuming that the period is like 0.5... In the paper i read about it they call that velocity "a" rotation velocity... but is given i m/s and angular velocity is in rad/s, so I am kinda confused about this
I would have called it a "tangential velocity". It will be given by the rotation rate (in rad/s) multiplied by the radius.

If the radius is measured in meters, the resulting tangential velocity will be in meters/sec
 
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