Satellite & Gravity Homework: Find Period of Revolution

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To find the period of revolution for a satellite in a circular orbit at 3.59 x 10^7 m above Earth's surface, the gravitational force provides the necessary centripetal acceleration. The relevant equations involve the gravitational constant, Earth's mass, and the radius of the orbit. The expected answer for the period of revolution is 24 hours. Users suggest calculating angular velocity using the formula mr(omega)^2 = GMm/r^2 and then relating it to the period. Further attempts to solve the problem may be posted for additional assistance.
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Homework Statement



It is proposed to place a communications satellite in a circular orbit rounf the equator at a height og 3.59 x 10^7m above the Earth's surface. Find the period of revolution of the satellite in hours and comment on result.

Values given:
Radius of Earth: 6.37 x 10^6m
Mass of Earth: 5.98 x 10^24kg
Gravitational Constant: 6.67x10^-11 m^3 kg^-1 s^-2

Homework Equations



Not sure which one you can you, but i think two different ones have to be used

The Attempt at a Solution



This is the only question which i couldn't answer, and when i tried several ways out, it got very far away from result. the answer should be :24 hrs
 
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You know that the centripetal accelration is provided by the gravitational force.

So,

mr(omega)^2 = GMm/r^2

SO you can calculate omega, the angular velocity.

Then you should have an equation relating the period tn the angular velocity.
 
thx, i'll try it out. If i get wrong result, i'll post my working to see what's wrong
 
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