SE- How to Determine Oil Temperature at Exit of Cylindrical Heat Exchanger?

AI Thread Summary
To determine the exit temperature of oil in a cylindrical heat exchanger, one must use the known characteristics of the exchanger, including the flow rates and specific heat capacities (Cp) of both oil and water. The global heat transfer coefficient (K) is also essential for calculating heat transfer. The heat transfer rate (Q) can be expressed as Q(oil) = m * Cp * dT, where m is the mass flow rate of the oil. Understanding the relationship between the heat transfer rate and mass flow rate is crucial, as it allows for the calculation of the oil's exit temperature based on the inlet conditions and the heat exchanged with the water. This approach provides a systematic way to solve the problem effectively.
Bibinou
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Hello,
I have some problems in resolving this exercise.
Consider a cylindrical heat exchanger, whose you know all caracteristics (such as : inside diameter, outside diameter and its length). This exchanger is used to cool an oil phase with water.

We know the flow of water, its Cp and its temperature, moreover we also know the flow of oil, its Cp and its temperature.
We also know the global transfert coefficient K expressed in kW.m-².K-1

How can we determine the temperature of oil at the exit of the exchanger?

Thank you very much.
 
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What are your thoughts about the problem at the moment?
 
I don't know how to begin,
perhaps by computing Q(oil)=m Cp dT but I don't know the mass of oil given that I don't know the time => I can't deduce it from the flow
 
Bibinou said:
I don't know how to begin,
perhaps by computing Q(oil)=m Cp dT but I don't know the mass of oil given that I don't know the time => I can't deduce it from the flow
If you know the flow rate of the oil and of the water, you know dm/dt. How does dQ/dt relate to dm/dt?

AM
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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