Simple Hamonic Motion(spring system)

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To determine the amplitude of simple harmonic motion that causes the smaller block to slip over the larger block, the maximum acceleration must be calculated, which is influenced by the static friction between the blocks. The static friction force can be expressed as F_friction = μ * m * g, where μ is the coefficient of static friction. The maximum acceleration of the system can be derived from the equation a = F/m, where F is the net force acting on the system. The relationship between the maximum displacement and acceleration can be established using the formula a = -ω²x, where ω is the angular frequency. Ultimately, solving for the amplitude will require integrating these concepts to find the point at which the static friction is overcome.
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Homework Statement




Two blocks (m=1Kg, M=10Kg) and a spring (k=200N/m) are arranged on a horizontal frictionless surface. The coefficient of static friction between the two blocks is 0.40 (the small block sits atop the large block). What amplitude of simple harmonic motion of the spring-blocks system puts the smaller block on the verge of slipping over the large block?


Homework Equations



I can calculate angular frequency using w=\sqrt{k/m}...not sure if this is helpful..and E=1/2kx_m^2



The Attempt at a Solution



The block will slip off when the acceleration of the system is a maximum, this happens at +/- x_m..im not sure how to rlate the friction into the equation, help getting started would be appreciated.

Thanks
 
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So you can solve what value of acceleration will cause the block's horizontal force to overcome static friction. You can then go back to the derivation of simple harmonic motion equations (i.e) mx''+kx=0, and figure out what the maximum initial displacement is.
 
Ok, so after finding Fmax and when calculating the accelration...do I use the mass of the system (11kg)?

and can I use (-w^2)x=a?
 
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