1. The problem statement, all variables and given/known data A particle moves along x axis It is initially at 0.270m moving with velocity of 0.140m/s and acceleration of -0.320m/s^2 Suppose it moves with constant acceleration for 4.50s. Find it's: a) position and velocity at end of time interval next assume it moves with simple harmonic motin for 4.50s and x= 0 is it's equillibrium position. Find it's: b) position and velocity at end of this time interval 2. Relevant equations [tex]x(t)= A cos (\omega t + \phi )[/tex] [tex]v(t)= - \omega A sin (\omega t + \phi ) [/tex] [tex]a(t)= - \omega ^2 A cos (\omega t + \phi) [/tex] 3. The attempt at a solution well I know for the first situation that: [tex]x_o[/tex]= 0.270 [tex]v_o[/tex]= 0.140m/s [tex]a_o[/tex]= -0.320m/s^2 and the acceration remain constant for 4.50s to find a) the postiion and velocity at end of time interval.... I was thinking that I would take the period (T) to equal T= 4.50s? and would I use 4.51 seconds and use the velocity as a function of time equation [tex]v(t)= - \omega A sin (\omega t + \phi ) [/tex] though I need the [tex] \phi [/tex]....hm.. and I think I'm lost here. can someone Please help me out with this?