Simple Harmonic Motion on a Uniform Meter Stick

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SUMMARY

The discussion focuses on calculating the frequency of oscillation for a uniform meter stick pivoted at one end and held horizontal by a spring with spring constant k. The derived frequency formula is (1/2π)√(3k/m), where m is the mass of the stick. Key equations utilized include τ = rFsinθ, f = (1/2π)√(k/m), and F = kx. Participants emphasize the importance of drawing a force diagram and applying torque equations to solve the problem.

PREREQUISITES
  • Understanding of torque and rotational dynamics
  • Familiarity with simple harmonic motion concepts
  • Knowledge of spring mechanics and Hooke's Law
  • Ability to differentiate and solve second-order differential equations
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  • Study the derivation of the frequency formula for simple harmonic oscillators
  • Learn about the application of torque in rotational motion problems
  • Explore the relationship between angular acceleration and linear displacement
  • Investigate the effects of varying spring constants on oscillation frequency
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NathanLeduc1
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Homework Statement


A uniform meter stick of mass M is pivoted on a hinge at one end and held horizontal by a spring with spring constant k attached at the other end. If the stick oscillates up and down slightly, what is its frequency?


Homework Equations


τ=rFsinθ
f=(1/2π)√(k/m)
F=kx
x=Acos(ωt)

The Attempt at a Solution


I'm really not sure how to get started on this one. If you could just provide me with a little start, I might be able to figure it out. Thanks.

The answer, according to the textbook, is (1/2π)sqrt(3k/m)
 
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Hi NathanLeduc1! :smile:
NathanLeduc1 said:
If you could just provide me with a little start, I might be able to figure it out.

Draw a force diagram for a small vertical displacement x, and find the force as a function of x. :wink:

(assume sinx = x)
 
Ok, so I set up a force diagram and did the following work but I'm stuck again...

At equilibrium:
Ʃτ=Kxol-mg(l/2)=0

After it's been stretched:
Ʃτ=K(x+xo)-mg(l/2)=Iα

This then simplifies to:
Iα=kxol

I wrote α as the second derivative of θ with respect to time but now I'm stuck. Where should I go from here? Thanks.
 
(just got up :zzz:)
NathanLeduc1 said:
Iα=kxol

I wrote α as the second derivative of θ with respect to time but now I'm stuck. Where should I go from here? Thanks.

α = x''/l :wink:
 

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