Simple Harmonic Motion - Period (T)

AI Thread Summary
A pendulum's oscillation period (T) is determined by its length (L) and gravitational acceleration (g), with the formula T = 2π√(L/g). Doubling both the mass of the bob and the length does not affect the period, as mass is not included in the equation for a pendulum. The new period remains T = 2π√(L/g), indicating that the period is dependent solely on the length and gravity. The discussion highlights a common confusion regarding the role of mass in the period of simple harmonic motion. Understanding these principles is essential for upcoming lectures and homework assignments.
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[SOLVED] Simple Harmonic Motion - Period (T)

1. A pendulum oscillates with a period T.

If both the mass of the bob and the length of the pendulum are doubled, the new period will be _____.




2. T = 2(pi) x rad (k/m)



3. Since L is not a part of the equation, it shouldn't affect the period - right? If that's true, then shouldn't the new period be: T/rad (2) ?

Sorry, I don't know how to insert symbols (i.e. pi and rad).
 
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That equation is for the time period of a spring. The equation for a pendulum is:

T = 2\pi \sqrt{\frac{L}{g}}
 
Thanks. I just figured that out after 5 mins of Googling. My professor hasn't gone over that yet. I guess that is what Friday's lecture is about...since this HW isn't due unti Sunday. Thanks again!
 
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