Simplest way to approximate sqrt of complex numbers

AI Thread Summary
To approximate the square root of complex numbers like sqrt(2 + 3i), one effective method is to express it in the form a + bi, leading to the equation x + iy = (a + bi)². This requires equating the real and imaginary parts to solve for 'a' and 'b'. Alternatively, using polar coordinates simplifies the process, where r = √(x² + y²) and θ = arctan(y/x), allowing the use of the formula sqrt(r(cos(θ) + i sin(θ))) = √r(cos(θ/2) + i sin(θ/2)). Both methods can be calculated by hand or with a spreadsheet for efficiency. Understanding these approaches aids in quickly approximating square roots of complex numbers without advanced calculators.
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I have a ton of homework with square roots of complex numbers. Like sqrt(2 + 3i)

What is the fastest way to break these down into its approximates like 1.67 + 0.895i without using a TI89/Maple/Matlab/Mathmatica.
 
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You could just do a general case for x+iy

\sqrt{x+iy} = a+bi \Rightarrow x+iy = (a+bi)^2and then just equate the real and imaginary parts. Though you will have to solve for 'a' and 'b'. Then you could just either put the numbers into a spreadsheet or calculate by hand when you get 'a' and 'b' in terms of 'x' and 'y'.
 
Or use the fact that \sqrt{r(cos(\theta)+ i sin(\theta))}= \sqrt{r}(cos(\theta/2)+ i sin(\theta/2)).

For x+ iy, r= \sqrt{x^2+ y^2} and \theta= arctan(y/x)
 
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