Skier coasts down hill speed at bottom?

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To determine the skier's speed at the bottom of a 10 m slope, one must consider both kinetic and potential energy. At the top, the skier has both kinetic energy (KE) and potential energy (PE), which can be calculated using the equations KE = 1/2mv^2 and PE = mgy. The total mechanical energy remains constant if no energy is lost, allowing for the calculation of speed at the bottom. Additionally, if friction does work of 2500 J, this energy loss must be accounted for in the final speed calculation. Understanding these principles will help solve the problem effectively.
araspante
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Hello! Just wondering if anyone could point me in the correct direction with these problems?

Homework Statement


"A skier coasts down a very smooth, 10 m high slope. If the speed of the skier on the top of the slope is 5.0 m/s, what is his speed at the bottom of the slope?"

and...

"If the skier has a mass of 60 kg, and the force of friction retards his motion by doing 2500 J of work, what is his speed at the bottom of the slope?"


I just can't seem to figure out what equation to use to figure this out.
Help!

Thanks SO much!
 
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welcome to pf.
At the top of the hill the skier has kinetic and potential energy - at the bottom he has just kinetic - since no energy is lost these are equal.
what are the equations for KE and PE?
 
thank you!

the equations are...

KE= 1/2mv^2
PE= mgy
 
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