Solar Heating Project: formula Q/t= A changing T/ R 1. The problem statement, all variables and given/known data At this moment I have a project whose due date forever looms closer and I'm still troublesome about how to conquer it. Objective: to design a solar heating system for my house building that will provide 50% of the heat. Step 1: I have to figure out how much heat my house looses each month using the formula Q/t= A changing T/ R. "...You can find changing temp. by looking at the "degree data" on the website. For example , if March has 1000 heating degree days, and there are 31 days in the month, the average temperature during March is 65 - 1000/31= 32.7 degrees Fahrenheit. " Where did the number "65" come from? Also, Ave. outside temp. = 18 - (degree heating days/ # of days in a month)= the answer (the final should be changed into Celsius) Here are my "A" measurements that I've simplified it into this here, presenting the areas: House L x W x H = 27 ft. x 17 ft. x 18 ft. 6 in. = 324 in. x 204 in. x 222 in. = 66096 in. x 222 in. = 14673312 in. / 144 sq in. = 101898 sq ft. Kitchen window #1 = 36 in. x 27 in. = 972 in. / 144 sq in. = 6. 75 sq ft Kitchen window #2 and Living room window #4 = 55 in. x 27 in. = 1485 in. / 144 sq in. = 10.3125 sq ft. x 2 = 20. 625 sq ft. Back Door and Front Door = 7 ft. x 3 ft. = 21 sq ft. x 2 = 42 sq ft. Basement Door = 6 ft. x 30 in. = 72 in. x 30 in. = 2160 in. / 144 sq in. = 15 sq ft. Basement windows #1, #2, #3, and #4 = 15 in x 33 in. = 495 in. / 144 sq in. = 3. 4375 sq ft. x 4 = 13. 75 sq ft. Kitchen closet Door, Living room closet Door, Bathroom Door, Me and sister closet Door, Upstairs hallways closet Door, Brothers closet Door, Mum and brothers closet Door = 80 in. x 28 in. = 2240 in. / 144 sq in. = 15.67 sq ft. x 7 = 108.9 sq ft. Living room windows #1, #2, and #3 = 52 in. x 32 in. = 1664 in. / 144 sq in. = 11.6 sq ft. x 3 = 34. 8 sq ft. Me and sister windows #1 and #2, Brothers windows #1 and #2, Mum and brothers windows #1 and #2 = 45 in. x 27 in. = 1215 in. / 144 sq in. = 8. 4375 sq ft. x 6 = 50. 625 sq ft. Me and sister Door, Brothers Door, Mum and brothers Door = 80 in. x 30 in. = 2400 in. / 144 sq in. = 16.67 sq ft. x 3 = 50 sq ft. "R" Values Wood = R 0.91 Insulating Glass = R 1.54 Sheetrock = R 0. 45 http://www.joeruff.com/artruff/physics/Thermodynamics/Example_solar_heating.pdf http://www.joeruff.com/artruff/physics/Thermodynamics/data.htm (these websites are needed to better continue- it gives the days of a month, but simply a head start and other neccesities like the temperature. I don't really know how to use this information. 100% needed.) 2. Relevant equations: Q/t= A changing T/ R Ave. outside temp. = 18 - (degree heating days/ # of days in a month)= answer in Celsius hopefully Q = C m changing Temp. Here are useful conversions: 1 BTU = 1055 Joules 1 kWh = 3413 BTU 1 m^3 of water = 1000 kg 1 meter = 3.3 ft. Fahrenheit = Celsius x 1.8 + 32 3. The attempt at a solution: Attempt included somewhere in the mix. Please help me get on track! I'm desperate at this momemt. Here is only step one. Step two would have pressured you not to help, so I took that part out. I dont know what to do. I edited parts of this. I read about what to do. Argh... Again, if you're familar with this formula: Q/t= A changing T/ R, then please assist me. The temperatures are on the websites. If the websites aren't assesible please comment, and Ill do what I can.