Solve a Short Parabola Question with 2π/3 Period | Example Problem

[tempeste]

http://img158.exs.cx/img158/5127/prob9cx.jpg

2pi/3 the period right?

 

[da_willem]

3sin(2\pi /3)-4=-3.89...

It's not even a function (or a pretty boring one), it's a number And why do you associate a sine with a parabola?

 

[tempeste]

I accidently made the assumption is was a parabola because the question asks for
amplitude, period, phase shift, domain, range, and vertical shift (but I know you can do this for a sine graph to)

Do you know how to graph it on a graphing calculator? I do not recall how to solve this type of problem =(

 

[da_willem]

Well as I said it's a pretty boring function, it's a number. It's just a straight horizontal (if you plot y on the vertical axis) line throught the point y=3sin(2\pi /3)-4=-3.89.... I'm not sure it's meaningful to assign a period to it as it's not periodic.

 

[tempeste]

there must be a mistake in the question, I am sure the book does not want us to graph a straight line over one full cycle?

I think it should be 3sin(x (not 0) - 2pi/3) -4
That would make much more sense

Thanks for your help will