Solve Atmospheric Pressure: Physics AP Edition

AI Thread Summary
To solve the pressure problem, consider the density of the fluid (850 kg/m³) and the atmospheric pressure (1.013 x 10^5 Pa). The pressure at a depth in the fluid is influenced by both the weight of the fluid above and the atmospheric pressure. The setup involves calculating the pressure using the formula that accounts for the weight of the fluid column and the atmospheric force. Understanding these principles will help in correctly setting up and solving the problem.
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This is a problem i have in my homework and i want to learn how to do these and get them right so please don't just give me an answer lol


The desity of the fluid in a tube is 850 kg/m cubic. THe pressure exerted by the atmospher is 1.013x10^5 Pa. What is the pressure P in the container?


I hate the book we are using because i don't think it gets too detailed on what we should do.. it gives 3 examples and none of them are like it is on the problem set..

its Physics An incremental Development SAXON and its our AP Physics book.
 
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HINT: At any level in the fluid, the fluid supports the weight of all the fluid directly above it - plus the weight of the all the atmosphere directly above it.
 
so how would i set this problem up? and thanks for the hint.. i didnt learn that in class so i added it to my personal notes :smile:

the way i think I am supposed to set this up is distance .21 m times 1.012x1065 x 850 kg/m cubic .. I am thinking the density may be throwing me off though..
 
At depth D, the weight of the fluid above that level is \rho A D g where A is the cross sectional area of the column and \rho is the mass density of the fluid. The force bearing downward by the atmosphere is P_A \times A. Those two forces are balanced by the pressure of the fluid at depth D: P_f \times A.

You should be able to work it out from there! :)
 
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