Solve ∫(e^x)/(√4-e^(2x)) w/ arcsin of x

ralfsk8
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Homework Statement



∫(e^x)/(√4-e^(2x))


Homework Equations



arcsin of x

The Attempt at a Solution



I know how the problem should be solved and have an idea of what the final answer will be. My only question is, how would I take out the four from the square root, in order to make it a 1? Can I just pull out 1/4?

Thank You
 
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ralfsk8 said:

Homework Statement



∫(e^x)/(√4-e^(2x))


Homework Equations



arcsin of x

The Attempt at a Solution



I know how the problem should be solved and have an idea of what the final answer will be. My only question is, how would I take out the four from the square root, in order to make it a 1? Can I just pull out 1/4?

Thank You

Yep. If you have \sqrt{4a+b} then in order to make the coefficient of a equal to 1, just factor out a 4 and then use the rule that \sqrt{ab}=\sqrt{a}\sqrt{b} so we'll have

\sqrt{4a+b}
=\sqrt{4(a+b/4)}
=\sqrt{4}\sqrt{a+b/4}
=2\sqrt{a+b/4}
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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