Solve Ohms Law: Resistance & Resistivity, 30W 6A Bulb

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Homework Help Overview

The discussion revolves around understanding resistance and resistivity in the context of a 30W, 6A bulb. The original poster seeks to determine the working temperature of the filament based on its resistance at a given temperature.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to define resistance and resistivity, applying Ohm's law and power equations to find resistance. They express confusion about the next steps in determining the filament's working temperature.

Discussion Status

Participants are engaged in clarifying the relationship between resistance and temperature, with some questioning the assumptions made about the proportionality of resistivity to absolute temperature. Guidance has been offered regarding the known values of resistance at different temperatures.

Contextual Notes

There is a noted ambiguity in the problem statement regarding the relationship between resistance and temperature, which some participants are attempting to clarify. The original poster acknowledges a lack of information on how to proceed from their calculations.

samblue
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Homework Statement



Define resistance and resistivity? A 30W, 6A bulb has a filiment which is directly prortional to the absolute temperature? At 37 degrees celsius the reisitance of the fimament is 015ohms. What is the working temperature of the filament?


Homework Equations



None given. But from my attempt I have used V=IR, P=IV.



The Attempt at a Solution



Resistance is a measure of a materials ability to pass charge. Reisistivity is a constant for each material which allows us to calculate the resitance, thus it is the ability for a material to pass current.

Ok so I worked out the current using P=IV
getting: I=6A

I then used this to work out the resistacne using V=IR
getring R=1.2ohms.

Im stuck here and don't know what to do, can someone please give me some hints or a rough idea about how to go about solving this problem? thanks
 
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> A 30W, 6A bulb has a filiment which is directly prortional to the absolute temperature?

This question should be a statement and has got something missing -- probably that the resistance is directly prortional to the absolute temperature. Please verify.
 
sorry. its the resistivity which is directly proportional to the absolute temperature.
 
You know the R at the working temp T -- you've solved it. You also know R at 37 C. Any ideas?
 
Shooting star said:
You know the R at the working temp T -- you've solved it. You also know R at 37 C. Any ideas?

No sorry i dont. I know this is almost certainly something simple which will make me feel stupid when I see the answer but at the moment I don't have the figgiest. My best guess would be to assume that the reistance and the temperature are related linerly?
 
Why would that be your guess? It's GIVEN in the problem, in the sentence you had mistyped. Refer post #3.
 

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