patapat
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Homework Statement
When light of wavelength 450 nm is shone on potassium, photoelectrons with stopping potential of 0.52 V are emitted. If the wavelength of the incident light is changed to 300 nm, the stopping potential is 1.90 V. Using only these numbers together with the values of the speed of light and the electron charge, do the following.
(a) Find the work function of potassium
(b) Compute a value for Planck's constant.
Homework Equations
eV_{0}=hf-\phi
The Attempt at a Solution
I'm not sure how to do this problem. Since they ask us to compute a value for Planck's constant I am not sure that we actually use the equation stated above. I assume that the work function is the same for both cases of wavelength and stopping potential, but I'm not sure what the relationship is.
Thanks in advance for the help.
-pat