Solve Photoelectric Effect: Find Work Function & Planck's Constant

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To solve the photoelectric effect problem, the work function of potassium and Planck's constant need to be determined using given wavelengths and stopping potentials. The relevant equation is eV₀ = hf - φ, where φ is the work function. The stopping potentials for 450 nm and 300 nm light are 0.52 V and 1.90 V, respectively, indicating that the work function remains constant across both scenarios. By setting up two equations based on the stopping potentials and solving for Planck's constant first, the work function can then be calculated. This method effectively utilizes the relationship between energy, frequency, and the work function.
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Homework Statement


When light of wavelength 450 nm is shone on potassium, photoelectrons with stopping potential of 0.52 V are emitted. If the wavelength of the incident light is changed to 300 nm, the stopping potential is 1.90 V. Using only these numbers together with the values of the speed of light and the electron charge, do the following.
(a) Find the work function of potassium
(b) Compute a value for Planck's constant.

Homework Equations


eV_{0}=hf-\phi


The Attempt at a Solution


I'm not sure how to do this problem. Since they ask us to compute a value for Planck's constant I am not sure that we actually use the equation stated above. I assume that the work function is the same for both cases of wavelength and stopping potential, but I'm not sure what the relationship is.
Thanks in advance for the help.

-pat
 
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it should be V_0 not V^0, thanks.
 
You can start with (b) and then do (a). Have two equations of (phi) = hf - eV_o, and set them equal to each other since they each the same phi value. You should then be able to solve for h. Then plug h into one of the equations to find phi
 
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