Solve Pulley Problem: Frustrated After Weeks of Trying

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The discussion revolves around solving a pulley problem involving workers and a platform. The initial confusion stems from how to account for forces in the system, particularly the tension and gravitational forces. After analyzing the forces, it becomes clear that the tension from the workers pulling the rope must be considered, leading to an adjustment in the equation for acceleration. The final formula for acceleration is clarified as a = (4*f - (m + m + 0.5*m)*g)/(m + m + 0.5*m), simplifying to (8f/5m) - g. The participants emphasize the importance of correctly identifying external forces in the system.
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Homework Statement


http://imgur.com/SE50jeP

Homework Equations


Fnet = m*a
FG = m*g

The Attempt at a Solution


I'm so confused about this problem and I still can't solve it after weeks.

The initial distance of the workers is irrelevant. If I treat the workers and the platform as a single system, then I don't have to worry about normal forces because they are internal forces. On my force body diagram, I have the tension force on the workers and platform due to the rope, f (two of them), and the weight force of the workers and the platform (together) as the external forces acting on the system:

(m + m + 0.5*m)*a = 2*f - (m + m + 0.5*m)*g

So the acceleration of the workers and the platform should be:

a = (2*f - (m + m + 0.5*m)*g)/(m + m + 0.5*m)

But the question doesn't allow you to enter "g", which suggests that the workers and the platform's weight is irrelevant. I don't understand why though. And what am I doing wrong? This is so frustrating. I have been trying to figure this problem out for weeks.

Thank you.
 
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I agree with you that g must feature in the answer, much as you have it, but you are missing something in the total external forces.
If you were to slice right across the diagram just above the workers' heads, what forces would you remove from the workers+platform system?
 
haruspex said:
I agree with you that g must feature in the answer, much as you have it, but you are missing something in the total external forces.
If you were to slice right across the diagram just above the workers' heads, what forces would you remove from the workers+platform system?

Since the workers are pulling with a force f on the rope, then due to Newton's Third Law, the rope would exert a force f on the workers in the opposite direction, so I am missing another 2 f forces, right?

So the acceleration should be:

a = (4*f - (m + m + 0.5*m)*g)/(m + m + 0.5*m)
 
FredericChopin said:
Since the workers are pulling with a force f on the rope, then due to Newton's Third Law, the rope would exert a force f on the workers in the opposite direction, so I am missing another 2 f forces, right?

So the acceleration should be:

a = (4*f - (m + m + 0.5*m)*g)/(m + m + 0.5*m)
Yes, or more simply ##\frac {8f}{5m}-g##
 
haruspex said:
Yes, or more simply ##\frac {8f}{5m}-g##

Thank you.
 
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