Solving a Basic Vectors Problem: Huck Finn's Velocity on a Raft

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Huck Finn's velocity relative to the river bank combines his northward movement of 1.0 m/s and the raft's eastward speed of 2.7 m/s. To solve for Huck's overall velocity, one can break the motion into X and Y components. The Pythagorean theorem is used to calculate the resultant magnitude, which is approximately 2.9 m/s. Additionally, trigonometric functions can determine the angle of this velocity relative to the river bank. Understanding vector addition and components is key to solving such physics problems effectively.
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Huck Finn walks North across a raft at a speed of 1.0 m/s while the raft is traveling east at a speed of 2.7 m/s relative to the river bank. What is the velocity of Huck relative to the river bank?



Well can't really think of any



I'm REALLY new to physics and I was stumped from the start. Apparently the answer is 2.9 m/s but I'm absolutely lost. Anyone help out a clueless fool?
 
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so try drawing a diagram of this. Break this up into X, and Y components (do you know what components are?) So huck is moving 1.0 m/s in the +y direction and 2.7 m/s in the +x direction due to the river. So how do we add vectors? we use the Pythagorean theorem to find the magnitude (although you don't really need to do this, you can just express your answer in terms of i and j unit vectors).

Once you find the magnitude, you can find the angle from the axis parallel to the river bank using trig inverse functions.
 
Thanks!
 
TheNovice said:
Thanks!

you're welcome. I presume you had no problems?
 
Yeah dude, it's simple after your explanation.
 
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