Solving a Tough Torques Problem: Finding Tension in a Cable | Homework Help

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To find the tension in the right cable supporting a 24kg mass on a 1.6m beam, the left end of the beam should be chosen as the pivot point for torque calculations. The forces acting on the beam include the weight of the mass and the beam itself, and the torque produced by these forces must be analyzed about the pivot. For equilibrium, the net torque around the pivot must equal zero. The solution confirms that the tension in the right cable is 190 N. This approach simplifies the problem and clarifies the distribution of torque between the two cables.
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Homework Statement



Two cables are used to support a 24kg mass on 1.6 m long 8.0 kg unifrom horizontal beam. One cable is on each end of the beam and the mass is 0.6m from the right cable. What is the tension in the right cable?

Homework Equations


t=Fd
Fg= mg



The Attempt at a Solution



I really don't know where to set my pivot point... I have tried multiple approaches.. the answer is 190 N. How do I separate the torque caused by the mass between the two cables?

Thanks,

Aneil
 
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Since you just need to find the tension in the right cable, pick the left side of the beam as your pivot point.

What forces act on the beam+masses? Where do they act? What torque does each force produce about your chosen pivot point? For equilibrium, what must the net torque be about any point?
 
Thanks Doc Al, seems simple in hindsight but you got me on the right track...:D Great help:)
 
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