Solving an Athlete's Shot Range Problem

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The discussion centers on calculating the distance a 16lbs shot lands when thrown at a 45-degree angle from a height of 6.5 feet with an initial speed of 44 ft/sec. The user successfully calculates the range from the launch point to where it is 6.5 feet above the ground, yielding a distance of 60.5 feet. However, they express uncertainty about determining the total distance to the ground (y=0). Participants suggest reviewing all relevant equations for projectile motion to aid in solving the problem. The thread emphasizes the need for a comprehensive understanding of projectile motion principles to complete the calculation.
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Homework Statement



An athlete puts a 16lbs shot at an angle of 45 degrees to horizontal from 6.5ft above the ground at initial speed of 44ft/sec. How far does the shot land?
g=32ft/s^2



Homework Equations



I can only calculated the range from the point it is fired to the point where it is 6.5 ft from the ground. But I have no clue calculating the distance traveled from the interval where it is 6.5ft above the ground to the ground(y=0).

The Attempt at a Solution



d = V0^2 sin2(45)/(32)
= (44)^2/ 32
= 60.5 ft
this is all i know. help please.
 
Last edited:
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thanks, I'll edit it.

oops, looks like I can't change the title.
 
You might want to write down all relevant equations for projectile motion and see what you can do with them.
 
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