Solving an Athlete's Shot Range Problem

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SUMMARY

The discussion focuses on calculating the landing distance of a 16lbs shot put launched at a 45-degree angle from a height of 6.5 feet with an initial speed of 44 ft/sec. The gravitational acceleration is given as 32 ft/s². The initial calculation provided yields a range of 60.5 feet, but the user seeks assistance in determining the total distance from the launch point to the ground level (y=0). Key equations for projectile motion are recommended for further exploration.

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Homework Statement



An athlete puts a 16lbs shot at an angle of 45 degrees to horizontal from 6.5ft above the ground at initial speed of 44ft/sec. How far does the shot land?
g=32ft/s^2



Homework Equations



I can only calculated the range from the point it is fired to the point where it is 6.5 ft from the ground. But I have no clue calculating the distance traveled from the interval where it is 6.5ft above the ground to the ground(y=0).

The Attempt at a Solution



d = V0^2 sin2(45)/(32)
= (44)^2/ 32
= 60.5 ft
this is all i know. help please.
 
Last edited:
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thanks, I'll edit it.

oops, looks like I can't change the title.
 
You might want to write down all relevant equations for projectile motion and see what you can do with them.
 

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