Engineering Solving Circuits with James: Finding I, Power, & Phase Angle

[James889]

Hi,

I have the following circuit
[PLAIN]http://img707.imageshack.us/img707/3024/upgp580.png

And i need to find the phasor current I, the power, reactive power and apparent power delivered by the source and state whether it's lagging or leading. But I am kind of stuck at the first step.

First i replace the capacitor with it's complex impedance
-j\frac{1}{333\cdot10\cdot10^{-6}} = -J300.3

And that is parallel with the 115ohm resistor, yielding:

\frac{1}{(1/115)+(1/-300)} = 186.48\ohm

And the phase angle

arctan\bigg(\frac{1/-300}{1/115}\bigg)= -20.93

So the current I is given by
\frac{1585\sqrt{2}}{186.48} \cdot cos(12-(-21)) = 10.08

Which is as usual incorrect.
According to the key the current I is 15.11 \angle 20.66

Please help
James

 

[n.karthick]

You should consider capacitive reactance as a complex quantity while calculating total impedance.