- #1
Kb1jij
- 19
- 0
I have been stumped trying to find the following integral:
[tex] \int \sqrt{1+x^2} dx [/tex]
I put it into my TI-89 calculator and it gave me and answer (that checks), but I cannot figure out how to do it by hand (is it possible?).
I tried using substitution and got:
[tex] \int \frac{\sqrt{u}}{\sqrt{u-1}} du [/tex]
If you then use integration by parts, it just flips the fraction. Any suggestions?
Thanks!
Tom
[tex] \int \sqrt{1+x^2} dx [/tex]
I put it into my TI-89 calculator and it gave me and answer (that checks), but I cannot figure out how to do it by hand (is it possible?).
I tried using substitution and got:
[tex] \int \frac{\sqrt{u}}{\sqrt{u-1}} du [/tex]
If you then use integration by parts, it just flips the fraction. Any suggestions?
Thanks!
Tom
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