Solving Force vs Time Graphs: Velocity Example #37

AI Thread Summary
To solve for velocity from a force versus time graph, the impulse (ΔP) is determined by calculating the area under the curve. The confusion arises from discrepancies in the impulse calculation, leading to doubts about the provided answer of -1 m/s. To find the correct velocity, one can use the relationship F=ma to calculate acceleration, then apply kinematic equations. Starting with an initial velocity (Vi) of 0 and a time duration of 20 seconds, the final velocity (Vf) can be derived using the formula Vf = Vi + at. Clarifying these steps can help resolve the confusion surrounding the problem.
kk727
Messages
54
Reaction score
0

Homework Statement


I was given this worksheet today:
http://www.mrwaynesclass.com/impulse/WS/momentum.pdf

However, I was not in school today nor when we started momentum. So I'm a little confused with the graphs. On a force versus time graph, how do you go about solving for velocity? An example problem would be #37. They give you the answer to be -1 m/s (answers are at the bottom) but how do you get there?


Homework Equations


P=mv
ΔP/ΔT = F
F=ma


The Attempt at a Solution



I figured that impulse (ΔP) would be area under the curve, so I calculated that. But using the force and time on the graph, the impulse didn't match up and I just got all confused and frustrated. Can anyone help?
 
Physics news on Phys.org
I just realized that the worksheet has two problems that are #37... -_- So I'm doubting that -1 m/s is the answer to this one. I'm still confused with trying to solve it, though!
 
kk727 said:
I just realized that the worksheet has two problems that are #37... -_- So I'm doubting that -1 m/s is the answer to this one. I'm still confused with trying to solve it, though!

There is no way it's -1...
Try doing this:
Using F=ma, you can get the acceleration, right? With the acceleration you can use the kinematics equations to get the answer.

You have:
Vi = 0
Acceleration = You find it
Time = 20 s
Vf = ? (solve)

So you can use:
vf = vi + at
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top