Solving Fourier Series Prob: Need Help With Integral Parts

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I've got parts of this problem but I'm stuck on some of the integration. See attached. Thanks!
 

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First, since an interval is 0 to \pi what are you integrating over 0 to \pi/2[/tex]?<br /> <br /> Second, since cos x is positive from 0 to \pi/2 and negative from \pi/2 to \pi, you can replace |cos(x)| with <br /> cos(x) from 0 to \pi/2 and with -cos(x) for \pi/2 to \pi.
 
HallsofIvy said:
First, since an interval is 0 to \pi what are you integrating over 0 to \pi/2[/tex]?<br /> Second, since cos x is positive from 0 to \pi/2 and negative from \pi/2 to \pi, you can replace |cos(x)| with <br /> cos(x) from 0 to \pi/2 and with -cos(x) for \pi/2 to \pi.
<br /> <br /> I changed the interval I was integrating over b/c that&#039;s part of the equation. You can&#039;t integrate from -l to l so you change it to 0 to l where l is half of the fundamental period and instead of multiplying the integral by 1/l, I changed it to 2/l. Is it easier to just integrate from -l to l?
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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