<br /> <br /> I changed the interval I was integrating over b/c that's part of the equation. You can't integrate from -l to l so you change it to 0 to l where l is half of the fundamental period and instead of multiplying the integral by 1/l, I changed it to 2/l. Is it easier to just integrate from -l to l?HallsofIvy said:First, since an interval is 0 to \pi what are you integrating over 0 to \pi/2[/tex]?<br /> Second, since cos x is positive from 0 to \pi/2 and negative from \pi/2 to \pi, you can replace |cos(x)| with <br /> cos(x) from 0 to \pi/2 and with -cos(x) for \pi/2 to \pi.