Solving Integration Troubles for Air Resistance Model

  • Thread starter Thread starter tomwilliam
  • Start date Start date
  • Tags Tags
    Integration
tomwilliam
Messages
141
Reaction score
2
I'm just playing around with a linear air resistance model to show that a marble, diameter 2cm, mass 13g, takes 3.96 seconds to fall 77m off a bridge to the water. I've done it by starting with

ma = mg - c1Dv

Where m is mass, D is diameter, v is velocity downwards and a is acceleration (g).
Now I can divide by m, then integrate twice with respect to t, and solve the quadratic equation to get the right answer. However, that involves a square root calculation. I'm preparing for an exam in which I won't have a calculator, so it might be best to do it a different way.
The book tells me to divide by mg - c1Dv, then integrate wrt t, giving
-1/k ln (g - kv) = t + A

Where k= c1D/m. Here's the problem...I'm not really sure how we got that result, nor where to go from here. Any helpful hints?
Thx in advance
 
Physics news on Phys.org
Not that it matters, but I have the value for c1, which I forgot to mention (1.7 x 10^-4)
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top