Solving Newtons 2nd Law Homework: Velocity of Rocket on Ground

AI Thread Summary
The discussion revolves around solving a homework problem related to Newton's Second Law, specifically focusing on the velocity of a rocket. The initial calculations for the rocket's weight and the effects of fuel ejection are confirmed as correct, with a weight of 30N and an initial velocity of 40 m/s for the remaining rocket. For the acceleration during fuel ejection, the calculated value is 200 m/s², leading to a force of 300N upwards. The main question concerns the rocket's velocity in both the east and upward directions, with the conclusion that the eastward velocity is zero due to no horizontal forces, while the upward velocity remains at 40 m/s if gravity is ignored. The discussion highlights the importance of considering gravity in the calculations, suggesting a potential upward velocity of 10 m/s if gravity is factored in.
iuhoosierz
Messages
10
Reaction score
0

Homework Statement


Ok this is kind of long. This is the 4th question on my homework assignment and I need to give background on the first 3 to make sure I got those correct.
1. I am sure on this since it was simply finding the weight of a rocket ship that has an intial mass of 3kg. Answer is 30N

2. Question is: Let's assume half the mass of the rocket is fuel and is spewed out nearly instantaneously. If the fuel for the rocket travels downward at a velocity of 40 m/s then what will be the initial velocity of the rest of the rocket? My answer is 40m/s Is this correct?

3. Instead of saying it is instantaneous let's say that the fuel was ejected in a time of 0.2 seconds.
A. Ignoring gravity during this time, what is the acceleration on the rocket during this time. I used A=change in Vel/Time and got 200 m/s
B. What is the force on the rocket during this time? I used F=MA and got 300N Up

Ok, IF these are all correct here is the question that I cannot figure out.

4. Near the ground there is no wind
A. What is the velocity of the rocket in the East Direction?
B. What is the velocity in the up direction?


Homework Equations





The Attempt at a Solution



I know velocity=change in position/time but not real sure what #'s to use here and really it doesn't make a lot of sense to me. Do I need to use 10m/s for gravity in here somewhere?
Thanks for any help.
 
Last edited:
Physics news on Phys.org
Your answers to 1, 2 and 3 are correct.

4-A. Zero, because there is no horizontal force.
4-B. Doesn't make sense if you ignore gravity. It'll be still 40 m/s.
 
Thanks. So if we weren't ignoring gravity would it be 10m/s?
 
iuhoosierz said:
Thanks. So if we weren't ignoring gravity would it be 10m/s?

How do you arrive at this value?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top