Engineering Solving RLC Circuit Response: Converting to Phasor Notation and Troubleshooting

AI Thread Summary
The discussion focuses on troubleshooting an RLC circuit response by converting to phasor notation. The user is confused about adding the impedances of capacitors and inductors, leading to a zero result, and is unsure how to proceed with circuit analysis. It is clarified that in the frequency domain, components can be treated like resistors with their respective impedances. The conversation highlights the resonance frequency of the circuit, where the LC combination has infinite impedance, resulting in the entire input voltage appearing at the output. Overall, the user is encouraged to seek further clarification from a teacher and explore node equations for better understanding.
sdusheyko
Messages
18
Reaction score
0
the problem statement is attached.

i've begun by converting everything into phasor notation but I'm not quite sure where to go from here. when i try to add the C and the L phasors, i get zero. this doesn't seem right.
another problem is i have no idea what to do when i get the impedances of the components added together. do i just add that to the input voltage for the answer?

any help appreciated.
 

Attachments

  • untitled.JPG
    untitled.JPG
    17.7 KB · Views: 423
Physics news on Phys.org
so I've converted the circuit to it's current source equivalent ( i can't remember if that's called thevenin or norton) and am able to add the impedances.

what to do from here?

i think I'm supposed to add the component impedances to the voltage input signal impedance and plug into v=ir for the voltage. but maybe not... I'm lost like i said. am i on the right track or far from it?
 
Yes, you have to go into the frequency domain. From here, you can treat all the components like they're resistors with their respective impedances

So, yeah. For your source, you have 2 at an angle -pi/4. Impedance of Res, cap and inductor are 1, -j, and j, respectively (i.e., Zc = -j/(wC))

Now you just have to do circuit analysis from here. How can you get y(t)? Since voltages are the same in parallel, what if we combine the inductor and cap?

-j // j = ([-j]*[j])/(j-j) = undefined.

Well that's weird. I'm not sure what that means physically. I was going to combine those two components and then use voltage division across the equivalent impedance there. Ask your teacher about this. Maybe try to do a node equation?
 
What you're finding is that when ω=1000, the LC combination has infinite impedance because that's the resonance frequency of the circuit. No current can flow, so the entire input voltage appears at the output.
 

Similar threads

Replies
8
Views
3K
Replies
32
Views
2K
Replies
25
Views
4K
Replies
6
Views
4K
Replies
1
Views
4K
Replies
34
Views
6K
Replies
26
Views
3K
Back
Top