Solving Schrodinger Eq.: Quantum #s for n=0,1,2

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Homework Help Overview

The discussion revolves around the Schrödinger equation and the associated quantum numbers for an atom, specifically focusing on identifying possible values for the quantum numbers n, l, m1, and Ms for n=0, 1, and 2.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants express confusion regarding the question's intent and seek clarification on how to approach the problem. There is a suggestion to start with n=0 and identify corresponding values for the other quantum numbers, though one participant later corrects this to n=1.

Discussion Status

The discussion is ongoing, with participants questioning the appropriateness of starting with n=0 and exploring the implications of beginning with n=1 instead. Some guidance has been offered regarding the sequence of quantum numbers.

Contextual Notes

There is a noted concern about the classification of the problem's difficulty level, with some participants questioning its placement in advanced physics versus introductory physics.

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Homework Statement


The solution of the Schrödinger equation for atom depends on four quantum numbers: the principal n, the orbital l, magnetic m1, and the spin Ms
n = 1, 2, 3, 4, ... (integers)
l = 0, 1, 2, ... (n-1)
m1 = -1, -1+1,...0...1-1, 1
Ms = -1/2, 1/2
List all possible values of n, l, m1, and ms for n= 0,1,2

Homework Equations





The Attempt at a Solution


I actually have no clue what the question is asking.. It is exactly how the professor typed it up as.. Can someone help me please?
 
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Can someone give me a hint on how to figure out the solution?
 
Begin with n=0. What are then the possible values for the other 3 quantum numbers ? Then the same question for n=1, etc.

EDIT: Sorry, n=1, of course. :D So n=1, what's l equal to ?
 
Last edited:
How is this in advanced physics?
 
Moderator's note: I have moved this thread to Introductory Physics. In the future, please post questions of this level in Introductory Physics.

By the way, there is a problem with n=0. I would start with n=1 instead.
 
sandy.bridge said:
How is this in advanced physics?

Sorry, I'm new to the forum..
 

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