Solving Static Friction Coefficient for Wooden Block on Table

  • Thread starter Thread starter runningirl
  • Start date Start date
  • Tags Tags
    Friction
AI Thread Summary
To solve for the coefficient of static friction between a wooden block and a table, the problem involves a 29.0 kg block with a 15.5 kg mass attached via a wire over a frictionless pulley. The block begins to slide when the tension from the hanging mass equals the static friction force. The normal force acting on the block is calculated by considering only the block's weight and the tension from the hanging mass. The correct approach requires isolating the forces on the block to accurately determine the static friction coefficient. Understanding these principles is crucial for solving the problem effectively.
runningirl
Messages
118
Reaction score
0

Homework Statement



A wooden block of mass 29.0 kg sits on a horizontal table. A wire of negligible mass is attached to the right side of the block and goes over a pulley (also of negligible mass, and frictionless), where it is allowed to dangle vertically. When a mass of 15.5 kg is attached to the wire, the block barely starts to slide. What is the coefficient of static friction between block and table?

Homework Equations



f=ma
Ff=coefficient (Fn)

The Attempt at a Solution



Fn=(29+15.5)*9.8?

got stuck after that.
 
Physics news on Phys.org
hi runningirl! :smile:

no, the weight of the block acts on the block only, the weight of the 15.5 kg mass acts on the 15.5 kg mass only …

to find Fnormal for the block, consider only the forces on the block (including the tension) :wink:
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Newton's law problem: Pushing 2 stacked blocks on a horizontal table
Replies
13
Views
3K
Finding the Coefficient of Static Friction
Replies
16
Views
6K
Coefficient of Friction question for a cart going down a wooden ramp
Replies
18
Views
3K
Static Friction Required to Keep the System from Moving (Two Boxes)
Replies
16
Views
3K
Coefficient of Friction when Normal Force is Reduced [HS]
Replies
5
Views
2K
Frictional Forces on a Wooden Crate with External Forces
Replies
1
Views
1K
How can I determine the instant the block overcomes static friction?
2
Replies
61
Views
3K
Two blocks, a fixed pulley and friction
Replies
4
Views
3K
A question about contact forces and friction
Replies
6
Views
5K
Statics and friction -- Two articulated rods connected to blocks
Replies
13
Views
2K

Hot Threads

Recent Insights

Back
Top