Solving Vector Calculus Problems in r1(t) and r2(t)

AI Thread Summary
The discussion focuses on solving vector calculus problems involving the curves r1(t) and r2(t). The user seeks assistance in determining the angle of intersection after identifying the point where the curves meet. They mention the formula |n||m| cos(a) = n.m, but express difficulty in finding the unit tangent vectors n and m at the intersection point. The known point of intersection is (3, -2, 25), which is crucial for substituting values for t and s. The thread emphasizes the need for guidance on calculating the unit tangent vectors to proceed with finding the angle of intersection.
Electro
Messages
48
Reaction score
0
Vector Calculus

Greetings everyone,

I have a problem: "Consider the curves r1(t)=(t, 1-t, 16+t^2) and
r2(t)=(8-s,s-7, s^2)
a) At what point do they meet?
b) Find their angle of intersection

The first part is easy, but I'm encountering some problems with b). To find the angle we need to apply the formula |n||m| cos(a)=n.m
The point is that we don't have the values of n and m. I tried to subsitute values for t and s (we also know the point of intersection) but still couldn't get it.
Someone can help?
Thanks
 
Last edited:
Physics news on Phys.org
Apply that formula |n||m| cos(a)=n.m where n and m are the unit tangent vectors of r1 & r2 at the point of intersection.
 
If we get the Unit Tangent Vectors then they are in terms of t. What do we substitute for t to get the value? The point we have is (3,-2,25) ->(x,y,z).
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top