If 100 mL test of water at 60°C is added to 100 mL of water at 20°C, then the final temperature of the water will be?
c=Specific Heat Capacity
Specific Heat Capacity of water = 4186
Quantity of Heat Energy=mass * Specific Heat Capacity of substance * temperature difference
The Attempt at a Solution
Water quantity at 60 degrees + Water quantity at 20 degrees = sum water quantity at new temperature
0.1 kg * 4186 * (60 - final temp) + 0.1 kg * 4186 * (final temp - 20) = 0.2 kg * 4186 * final temp
418.6 (60-final temp) + 418.6 (final temp-20) = 837.2 * final temp
25116 - 418.6final temp + 418.6final temp - 8372 = 837.2final temp
final temp= 20 degrees celsius
So, the final temp is 20°C ??? that doesnt make sense?