Solving a Copper Metal Heat Exchange Problem: Seeking Advice

AI Thread Summary
The discussion focuses on a heat exchange problem involving two identical copper blocks at different temperatures, seeking to understand the heat transfer during their thermal equilibrium. The specific heat of copper is noted as 0.1 kilocalorie/kilogram K, which is crucial for calculating the energy required to change the temperature of one block. It is emphasized that while the final temperature will be the same for both blocks, the amount of heat exchanged can vary based on the materials and sizes involved. The conversation highlights the distinction between heat and temperature, reinforcing a fundamental thermodynamic principle. Understanding these concepts is key to solving the problem effectively.
kirste
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Just looking through some old papers and found a problem that I don't know how to solve.

Two identical 1.0-kilogram blocks of copper metal, one initially at a temp OC and the other initially at a temp of 100C are enclosed in a perfectly insulating container. The two blocks are initially separated. When the blocks are placed in contact, they come to equilibrium at a final temp of Tf. The amount of heat exchanged between the two blocks in this process is equal to which of the following? (the specific heat of copper metal is equal to 0.1 kilocalorie/kilogram K

I know that Spec. Heat=J/g.C, but other than that can someone give some general advice on how to solve this problem?

Thank you
 
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Assume they come to equilibrium at a temperate half way between 0,100
So work out the energy needed to heat a block by 50K
 
thats exactly what I needed to know :)
 
It's an important difference between heat and temperature - actually pretty much the fundamental law of thermodynamics = Temperatures will always end up the same however much heat has to be transferred to make that happen.

If the blocks were different materials or size they would still end up at the same temperature although not necessarily 50deg - and the energy flowing between them would not be the same.
 
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