Sphere rotation expression help

AI Thread Summary
The discussion focuses on deriving an expression for the total time a sphere of radius R, projected up an inclined plane at angle @ with initial speed Vo and angular velocity Wo, takes before stopping. The sphere rolls due to friction, which initially acts backward to increase angular velocity while decreasing linear velocity. Once rolling is achieved, friction's direction changes to maintain rolling as the sphere slows down. The time to reach rolling conditions is calculated as (2Vo - 2WoR)gsin@ + 5, with the total time until stopping estimated at 14/3 seconds. The analysis emphasizes the dynamic interplay between linear and angular motion under the influence of friction.
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Homework Statement


1) A sphere of radius R is projected up an inclined plane of angle @ with initial speed Vo and angular velocity Wo in a direction in which it can roll.The coefficient of friction is tan@/7 and it is given that Vo> RWo. Obtain an expression for the total time of motion of the sphere up the plane before it stops.

Comment on my working.

Homework Equations



I = 2/5mr^2
Impulse = delta mv = ft
Angular impulse = delta Iw = ftr ( r is perpendicular dist from axis of rotation)

The Attempt at a Solution



Concept:
Since Vo > RWo so the sphere will first try to perform rolling which is caused due to the presence of friction. Direction of friction will be backward along the incline so that the W increases and V decreases which eases the attainment of rolling. Once rolling has been achieved , friction changes direction(whoa!) because now to keep up with the decreasing V, it has to decrease W also.This will happen till the block is at an instantaneous rest.

Result:

First I found the time taken to reach rolling conditions which came out to be equal to (2Vo - 2WoR)gsin@ + 5 and the time after rolling till the time it comes to a stop came out to be 14/3 seconds (LOL?)
 
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